Seymour Brunson
American Mormon leader
About Seymour Brunson
Lived 1798 – 1840 (aged 41). Seymour Brunson was a bodyguard.
Seymour Brunson (September 18, 1799 – August 10, 1840) was an early convert to the Church of Jesus Christ of Latter-day Saints. He is most noted since it was at a speech given at his funeral that Joseph Smith first presented the doctrine of Baptism for the Dead.
Brunson was born on September 18, 1799, in Virginia. His parents were Reuben and Salley Clark Brunson. In 1813, at the age of 14, he enlisted in the United States military as a 16-year-old and served during the War of 1812.
In 1823, Brunson married Harriet Matilda Gould. They eventually had seven children.
Brunson was baptized a member of Church of Christ in January 1831 in Strongsville, Ohio. and as a lieutenant colonel in the Hancock County Militia. He also served as one of Joseph Smith's bodyguards.
He died on August 10, 1840.
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Important facts
People in Seymour Brunson's life
Named in this biography and alive at the same time
Contemporaries
People whose lives overlapped Seymour Brunson's
Frequently asked questions
Who was Seymour Brunson?
American Mormon leader
When was Seymour Brunson born?
Seymour Brunson was born on 18 September 1798.
When did Seymour Brunson die?
Seymour Brunson died on 10 August 1840.
What was Seymour Brunson's occupation?
Seymour Brunson was a bodyguard.
Sources & further reading
Cite this page
APA: Biography.guide. (2026). Seymour Brunson. https://biography.guide/seymour-brunson/
MLA: "Seymour Brunson." Biography.guide, https://biography.guide/seymour-brunson/.
Chicago: "Seymour Brunson." Biography.guide. https://biography.guide/seymour-brunson/.
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